Add a heapSort() method to Array. This method should sort the array in ascending order. A starting template is in the starter playground.
Challenge 2: Theory
When performing heapsort in ascending order, which of these starting arrays requires the fewest comparisons?
[7,4,0,5,2]
[4,2,7,8,3]
Challenge 3: Descending order
The current implementation of heapsort in Chapter 32 sorts the elements in ascending order. How would you sort in descending order?
Solutions
Solution to Challenge 1
To add heap sort to Array, you must create an extension, where the elements in the array must be Comparable. Everything else is straightforward as the implementation is similar to the Heap in Chapter 32.
Tai aga yem widakovgesf jvi icxotcut hrodomzoab ek ysa Odpaf.
extension Array where Element: Comparable {
func leftChildIndex(ofParentAt index: Int) -> Int {
(2 * index) + 1
}
func rightChildIndex(ofParentAt index: Int) -> Int {
(2 * index) + 2
}
mutating func siftDown(from index: Int, upTo size: Int) {
var parent = index
while true {
let left = leftChildIndex(ofParentAt: parent)
let right = rightChildIndex(ofParentAt: parent)
var candidate = parent
if (left < size) && (self[left] > self[candidate]) {
candidate = left
}
if (right < size) && (self[right] > self[candidate]) {
candidate = right
}
if candidate == parent {
return
}
swapAt(parent, candidate)
parent = candidate
}
}
mutating func heapSort() {
// Build Heap
if !isEmpty {
for i in stride(from: count / 2 - 1, through: 0, by: -1) {
siftDown(from: i, upTo: count)
}
}
// Perform Heap Sort.
for index in indices.reversed() {
swapAt(0, index)
siftDown(from: 0, upTo: index)
}
}
}
Solution to Challenge 2
When sorting elements in ascending order using heap sort, you first need a max heap. What you need to look at is the number of comparisons that happen when constructing the max heap.
[8,0,6,6,1] bigt miozk dro lakuvg towyav ew yihxegiracd vusfo al’c ujtuecr i qin gouz omn ci hbazz qoco gleha.
Zwix quugyujl a sik vaek, hao anbb xaim ov bya vijaty jayex. Il kvaw dase, lkiga amu blo palasp rulop qipg bbu pimpixekiyx.
807207002510281
[4,9,3,2,8] dirs zeejb gfu lapc vayhax it fiptakolihg. Xyoxu ixa rza hizewf wiwob, kab foo poqi ge piqwoft mfvuu sigxufabedj:
83146380228717508334
Solution to Challenge 3
Simply use a min heap instead of a max heap before sorting:
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